Show numeric permissions on ls

ls -l | awk '{k=0;for(i=0;i<=8;i++)k+=((substr($1,i+2,1)~/[rwx]/)*2^(8-i));if(k)printf("%0o ",k);print}'

Discussion

Real name:

E-Mail:

Enter your comment:

Please fill all the letters into the box to prove you're human. T A U᠎ I K Please keep this field empty:

Subscribe to comments